Solution of task 108 of Chemistry Book Shimanovich 2003
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108. Based on the values of the standard heats of formation and absolute standard heats
entropy of the corresponding substances, calculate the G0298 reaction, proceeding according to the equation:
NH3 (g) + HCl (g) = NH4Cl (k)
Can this reaction proceed spontaneously under standard conditions?
Answer: -92.08 kJ
entropy of the corresponding substances, calculate the G0298 reaction, proceeding according to the equation:
NH3 (g) + HCl (g) = NH4Cl (k)
Can this reaction proceed spontaneously under standard conditions?
Answer: -92.08 kJ