ОХ144 The reaction of a compound of nitrogen with hydro
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144. The reaction of a compound of nitrogen with hydrogen is by the equation:
N2 + 3H2 = 2NH3
The equilibrium concentrations of the participating substances were (mol / L): [N2] = 0.01; [H2] = 3,6; [NH3] = 0.40. Determine the equilibrium constant.
N2 + 3H2 = 2NH3
The equilibrium concentrations of the participating substances were (mol / L): [N2] = 0.01; [H2] = 3,6; [NH3] = 0.40. Determine the equilibrium constant.