143. Solving a chemistry problem
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6.36. Using the benzene adsorption isotherm, determine the specific surface area of the adsorbent (Т = 293 K, S0 = 49 * 10–20 m2). The volume of adsorbed gas is reduced to normal conditions:
P / Ps 0.08 0.16 0.25 0.35 0.45 0.52
A * 102, m3 / kg 1.03 1.37 1.70 1.99 2.44 2.82
P / Ps 0.08 0.16 0.25 0.35 0.45 0.52
A * 102, m3 / kg 1.03 1.37 1.70 1.99 2.44 2.82
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